If we crafted a GraphQL Error in our Resolver code, don't mess with it,

return it untouched.

Author: abourget

internal/exec/subscribe.go

@@ -112,7 +112,11 @@ func (r *Request) Subscribe(ctx context.Context, s *resolvable.Schema, op *query
 
 				if subErr, ok := resp.Interface().(errors.SubscriptionError); ok {
 					if err := subErr.SubscriptionError(); err != nil {
-						c <- &Response{Errors: []*errors.QueryError{errors.Errorf("%s", err)}}
+						if gqlError, ok := err.(*errors.QueryError); ok {
+							c <- &Response{Errors: []*errors.QueryError{gqlError}}
+						} else {
+							c <- &Response{Errors: []*errors.QueryError{errors.Errorf("%s", err)}}
+						}
 						return
 					}
 				}

subscriptions.go

@@ -3,6 +3,7 @@ package graphql
 import (
 	"context"
 	"errors"
+
 	qerrors "github.com/graph-gophers/graphql-go/errors"
 	"github.com/graph-gophers/graphql-go/internal/common"
 	"github.com/graph-gophers/graphql-go/internal/exec"