Compile an integer to an exectuable that exits with the given number

Author: rui314

.gitignore

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+**/*~
+**/\#*
+**/*.o
+**/*.s
+**/a.out
+/tmp*
+/chibicc

Makefile

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+CFLAGS=-std=c11 -g -fno-common
+
+chibicc: main.o
+	$(CC) -o chibicc main.o $(LDFLAGS)
+
+test: chibicc
+	./test.sh
+
+clean:
+	rm -f chibicc *.o *~ tmp*
+
+.PHONY: test clean

main.c

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+#include <stdio.h>
+#include <stdlib.h>
+
+int main(int argc, char **argv) {
+  if (argc != 2) {
+    fprintf(stderr, "%s: invalid number of arguments\n", argv[0]);
+    return 1;
+  }
+
+  printf("  .globl main\n");
+  printf("main:\n");
+  printf("  mov $%d, %%rax\n", atoi(argv[1]));
+  printf("  ret\n");
+  return 0;
+}

test.sh

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+#!/bin/bash
+assert() {
+  expected="$1"
+  input="$2"
+
+  ./chibicc "$input" > tmp.s || exit
+  gcc -static -o tmp tmp.s
+  ./tmp
+  actual="$?"
+
+  if [ "$actual" = "$expected" ]; then
+    echo "$input => $actual"
+  else
+    echo "$input => $expected expected, but got $actual"
+    exit 1
+  fi
+}
+
+assert 0 0
+assert 42 42
+
+echo OK